Markdown 数学公式

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代码结果
a+ba+ba+b
x_1^2x12x_1^2
x_{22}x22x_{22}
x^{(n)}x(n)x^{(n)}
^*x^*∗x∗^*x^*
\frac{x+y}{2}x+y2\frac{x+y}{2}
\frac{1}{1+\frac{1}{2}}11+12\frac{1}{1+\frac{1}{2}}
\sqrt[3]{3}33\sqrt[3]{3}
\sqrt[3]{1+\sqrt[3]{3}}1+333\sqrt[3]{1+\sqrt[3]{3}}
\sum_{k=1}^{n} \frac{1}{1+k}∑k=1n11+k\sum_{k=1}^{n} \frac{1}{1+k}
lim^{x \to \infty}_{y \to 0}{\frac{x}{y}}lim⁡y→0x→∞xy\lim^{x \to \infty}_{y \to 0}{\frac{x}{y}}
\displaystyle \lim^{x \to \infty}_{y \to 0}{\frac{x}{y}}lim⁡y→0x→∞xy\displaystyle \lim^{x \to \infty}_{y \to 0}{\frac{x}{y}}
\int_{a}^{b} \frac{1}{1+x} dx∫ab11+xdx\int_{a}^{b} \frac{1}{1+x} dx
\int_{a}^{b} f(x)dx∫abf(x)dx\int_{a}^{b} f(x)dx
\int_a^b f(x) \, dx∫abf(x) dx\int_a^b f(x) \, dx
\iint∬\iint
\displaystyle \int∫\displaystyle \int
\partial∂\partial
\pm±\pm
\mp∓\mp
\times×\times
\div÷\div
\mid or |∣\mid
\cdot⋅\cdot
\ast∗\ast
\forall∀\forall
\exists∃\exists
\nabla∇\nabla
\triangle△\triangle
\leq≤\leq
\geq≥\geq
\leqslant⩽\leqslant
\ngeq≱\ngeq
\approx≈\approx
\neq≠\neq
\infty∞\infty
\cdots⋯\cdots
\prod∏\prod
\sim∼\sim
\rightarrow→\rightarrow
\Rightarrow⇒\Rightarrow
\xrightarrow[\text{world}]{\text{hello}}→worldhello\xrightarrow[\text{world}]{\text{hello}}
\Longrightarrow⟹\Longrightarrow
\Leftrightarrow⇔\Leftrightarrow
\in∈\in
\notin∉\notin
\subset \supset⊂⊃\subset \supset
\subseteq \supseteq⊆⊇\subseteq \supseteq
\cup \cap∪∩\cup \cap
a \! ba ⁣ba\!b
a babab
a \, ba ba\,b
a \; ba  ba\;b
a\ ba ba\ b
a \quad baba\quad b
a \qquad baba\qquad b
\vec{a}a⃗\vec{a}
\dot{x}x˙\dot{x}
\ddot{x}x¨\ddot{x}
\bar{a}aˉ\bar{a}
\hat{a}a^\hat{a}
\stackrel{\rm def}{=}=def\stackrel{\rm def}{=}
a \atop =a=a \atop =
a \choose b(ab)a \choose b
\imath、\jmathı、ȷ\imath、\jmath
\overline{xyz}xyz‾\overline{xyz}
\underline{x+y}x+y‾\underline{x+y}
()()()
[][][]
\{ \}{}\{ \}
\lbrace \rbrace{}\lbrace \rbrace
\left\{{}\left\{ \right\}
\langle \rangle⟨⟩\langle \rangle
\Bigg( \bigg( \Big( \big( ((((((\Bigg( \bigg( \Big( \big( (
|∥\|
\because∵\because
\therefore∴\therefore
\left( \sum_{i=1}^n \frac{x^2}{1-x} \right)(∑i=1nx21−x)\left( \sum_{i=1}^n \frac{x^2}{1-x} \right)
\begin{matrix} 1&2 \\ 3&4 \end{matrix}1234\begin{matrix} 1&2 \\ 3&4 \end{matrix}
\begin{pmatrix} 1&2 \\ 3&4 \end{pmatrix}(1234)\begin{pmatrix} 1&2 \\ 3&4 \end{pmatrix}
\begin{bmatrix} 1&2 \\ 3&4 \end{bmatrix}[1234]\begin{bmatrix} 1&2 \\ 3&4 \end{bmatrix}
\begin{vmatrix} 1&2 \\ 3&4 \end{vmatrix}∣1234∣\begin{vmatrix} 1&2 \\ 3&4 \end{vmatrix}
\begin{Vmatrix} 1&2 \\ 3&4 \end{Vmatrix}∥1234∥\begin{Vmatrix} 1&2 \\ 3&4 \end{Vmatrix}
\begin{aligned} x = {}& a+b+c+{} \\ &d+e+f+g \end{aligned}x=a+b+c+d+e+f+g\begin{aligned} x = {}& a+b+c+{} \\ &d+e+f+g \end{aligned}
\begin{aligned} x = a+b+c+{} \\ &&&&&d+e+f+g \end{aligned}x=a+b+c+d+e+f+g\begin{aligned} x = a+b+c+{} \\ &&&&&d+e+f+g \end{aligned}
\overbrace{a+\underbrace{b+c}_{1.0}+d}^{2.0}a+b+c⏟1.0+d⏞2.0\overbrace{a+\underbrace{b+c}_{1.0}+d}^{2.0}
\alphaα\alpha
{alpha}alpha{alpha}
\mbox{what}whatwhat
\emptyset∅\emptyset
\mathbf{R}R\mathbf{R}
\mathbb{R}R\mathbb{R}
\mathcal{R}R\mathcal{R}
\bullet∙\bullet
\Vert u \Vert_2∥u∥2\Vert u \Vert_2
\succeq⪰\succeq
\mathbf{X} = \left( \begin{matrix}
x\_11 & x\_12 & \ldots \\
x\_21 & x\_22 & \ldots \\
\vdots & \vdots & \ddots
\end{matrix}  \right)

X=(x_11x_12…x_21x_22…⋮⋮⋱)\mathbf{X} = \left( \begin{matrix} x\_11 & x\_12 & \ldots \\ x\_21 & x\_22 & \ldots \\ \vdots & \vdots & \ddots \end{matrix} \right)

\mathbf{X} = \left( \begin{array}{ccc}
x_{11} & x_{12} & \ldots \\
x_{21} & x_{22} & \ldots \\
\vdots & \vdots & \ddots
\end{array}
\right)

X=(x11x12…x21x22…⋮⋮⋱)\mathbf{X} = \left( \begin{array}{ccc} x_{11} & x_{12} & \ldots \\ x_{21} & x_{22} & \ldots \\ \vdots & \vdots & \ddots \end{array} \right)

\begin{gathered}
a=b+c+d \\
x=y+z
\end{gathered}

a=b+c+dx=y+z\begin{gathered} a=b+c+d \\ x=y+z \end{gathered}

\begin{aligned}
a&=b+c+d \\
x&=y+z
\end{aligned}

a=b+c+dx=y+z\begin{aligned} a&=b+c+d \\ x&=y+z \end{aligned}

y=\begin{cases}
-x, \quad x \leq 0 \\
x, \quad x > 0
\end{cases}

y={−x,x≤0x,x>0y=\begin{cases} -x, \quad x \leq 0 \\ x, \quad x > 0 \end{cases}

\left(
\begin{array}{|c|c|}
1&2 \\
\hline 
3&4
\end{array}
\right)

(1234)\left( \begin{array}{|c|c|} 1&2 \\ \hline 3&4 \end{array} \right)

\begin{array}{|c|c|}
\hline
1&2 \\
\hline
3&4 \\
\hline
\end{array}

1234\begin{array}{|c|c|} \hline 1&2 \\ \hline 3&4 \\ \hline \end{array}

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